Answer:
For 3/4-inch EMT (actual ID ≈ 0.740"), the maximum number of #12 THHN conductors is determined by Table 1, Chapter 9 of the NEC, using the 40% fill rule for more than two conductors.
Step 1: Find Conduit Fill Capacity
- 3/4" EMT allows 40% fill (per Table 1, Chapter 9).
- From Table 4, 3/4" EMT has a total area of 0.598 in².
- 40% of 0.598 = 0.239 in² available for conductor fill.
Step 2: Find Area of #12 THHN
- From Table 5, #12 THHN has an area of 0.0133 in².
Step 3: Calculate Number of Conductors
- 0.239 ÷ 0.0133 ≈ 17.97
- Maximum = 17 #12 THHN conductors
For Mixed Sizes:
Use the same method:
- Find the area of each conductor size from Table 5.
- Multiply each by the number of conductors of that size.
- Add all areas together.
- Total must not exceed 0.239 in² (for 3/4" EMT at 40% fill).
Example: (10 × 0.0133) + (2 × 0.0211) = 0.133 + 0.0422 = 0.175 in² → OK
Note: If more than 3 current-carrying conductors are installed, derating per Table 310.15(C)(1) may apply. Also, a grounding conductor (if required) counts toward fill but is not current-carrying.
Let me know if you need help with derating or specific wire combinations.