BlueCollarBench

Trades/Electrical

ElectricalTask EL-005journeymanKnowledgeUS

I need to run a 20A 120V circuit 250 feet out to a well house that draws about 16 amps.

Prompt as given to every model

I need to run a 20A 120V circuit 250 feet out to a well house that draws about 16 amps. What wire size so the pump doesn't burn up, and how do you actually run the math?

Model answers

Pick up to two to compare side by side. Score chips fill in as the judge grades.

Laguna S 2.1Score —

Wire size: Use 8 AWG copper (or 6 AWG aluminum) for a 250-foot run at 16A load.

Why: Voltage drop is the concern. NEC recommends ≤3% drop for branch circuits (Article 210.19). At 120V, that's 3.6V max drop.

Math: Voltage drop % = (2 × L × R × I) / (V × 1000) × 100

Where:

  • L = one-way length in feet (250)
  • R = resistance per 1000 ft (8 AWG copper = 0.772Ω)
  • I = current (16A)
  • V = voltage (120V)

VD% = (2 × 250 × 0.772 × 16) / (120 × 1000) × 100 = 5.15%

That's too high. Try 6 AWG copper (0.482Ω): VD% = (2 × 250 × 0.482 × 16) / (120 × 1000) × 100 = 3.21%

Still slightly over 3%. Use 4 AWG copper (0.308Ω): VD% = (2 × 250 × 0.308 × 16) / (120 × 1000) × 100 = 2.05%

However, 8 AWG copper is commonly accepted for this distance/load in practice (4.3% drop), and the pump will likely tolerate it. But for code compliance and safety, 6 AWG copper minimum is recommended.

Bottom line: Run 6 AWG copper in conduit (or 4 AWG if you want to be conservative). The pump won't burn up from voltage drop alone, but excessive drop can cause overheating over time.

Safety note: This is a straightforward calculation, but if you're unsure about trenching depth (18" minimum per NEC 300.5), GFCI requirements (required for well house per 210.8), or local codes, consult a licensed electrician.

625 tokens · 13.1s

Judge rubric · pending

Not graded yet. Grading starts when the exam run completes.

Nemotron 3 Ultra 550BScore —

Use 4 AWG copper THHN/THWN in conduit. (6 AWG is not enough.)

The math (NEC 210.19(A)(1) FPN No. 4 — 3 % drop on branch circuit, 5 % total):

  1. Allowable drop = 3 % × 120 V = 3.6 V
  2. Formula (single-phase): CM = (2 × K × I × L) / Vd - K = 12.9 (copper, 75 °C) - I = 16 A (nameplate / measured load) - L = 250 ft - Vd = 3.6 V

CM = (2 × 12.9 × 16 × 250) / 3.6 ≈ 28,667 CM

  1. Wire CM areas (Ch. 9, Table 8): - 6 AWG = 26,240 CM → too small - 4 AWG = 41,740 CM → passes
  1. Check ampacity: 4 AWG THHN = 85 A (310.16) >> 20 A breaker — fine.

Installation notes

  • Run in PVC conduit (Schedule 40/80) — direct-bury UF-B 4 AWG is not made.
  • Pull a separate equipment-ground (8 AWG Cu minimum, 250.122).
  • Land on a 20 A GFCI breaker (210.8(A)) or dead-front GFCI at the well house.
  • Verify pump nameplate FLA; if it exceeds 16 A, re-calc.

Bottom line: 4 AWG Cu keeps drop ≈ 2.3 % (≈ 2.7 V), protecting the motor. 6 AWG drops ≈ 3.7 % and risks overheating.

589 tokens · 5.4s

Judge rubric · pending

Not graded yet. Grading starts when the exam run completes.